Can someone please help with these 2 word problems ASAP.4. A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouverand Regina is 1730 km. If the flight from Vancouver to Regina on a commercial airplane takes140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route? 5. A man goes fishing in a river and wants to know how long it will take him to get 10km upstreamto his favourite fishing location. The speed of the current is 3 km/hr and it takes his boat twiceas long to go 3km upstream as is does to go 4km downstream. How long will it take his boat to get to his fishing spot?

Answer:4.     4.66hours5.  time_trip = 2.777 hStep-by-step explanation:4. A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver and Regina is 1730 km. If the flight from Vancouver to Regina on a commercial airplane takes 140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route? We know thatSpeed_commercial = distance/ time_commSpeed_commercial = 1730 km/ time_commThen,Speed_jet = distance/ time_jet = 2*Speed_commercial Speed_jet =   1730 km/ time_jet = 2*Speed_commercial time_comm = 2.333 h + time_jet 1730 km/ time_jet = 2*1730 km/ time_commtime_comm = 2*time_jettime_comm = 2*(time_comm  - 2.333h)time_comm = (2*time_comm  - 4.666h)time_comm  = 4.666 h5. A man goes fishing in a river and wants to know how long it will take him to get 10km upstream to his favourite fishing location. The speed of the current is 3 km/hr and it takes his boat twice as long to go 3km upstream as is does to go 4km downstream. How long will it take his boat to get to his fishing spot?Distance = 10 km upstreamSpeed_current = 3 km/hUpstream(Speed_boat - Speed_current)  = 3 km / (2*time_downstream)Downstream(Speed_boat + Speed_current)  = 4 km / (time_downstream)We subtract both equations(Speed_boat + Speed_current) - (Speed_boat - Speed_current) = 4 km / (time_downstream) - 3 km / (2*time_downstream)2*Speed_current = (5/2 km)/ time_downstream2*(3 km/h)= (5/2 km)/ time_downstreamtime_downstream = 0.416 h(Speed_boat + 3km/h)  = 4 km / (0.416 h)Speed_boat  = 6.6 km/hTrip upstream(Speed_boat - Speed_current)  = 10 km / (time_trip)time_trip = 10 km/(3.6 km/h) = 2.777 htime_trip = 2.777 h