wth is the value of b my guy triangle ABC is a right triangle and cos (22.6°)=b/13. Solve for b and round the the nearest whole number. which equation correctly uses thw value of b to solve for a?tan(22.6)=a/13tan (22.6)=13/atamd(22.6)=a/12tan(22.6) =12/a

Answer: 1) [tex]b=12[/tex] 2) [tex]tan(22.6\°)=\frac{a}{12}[/tex] (Third option) Step-by-step explanation: Remember that: [tex]cos\alpha=\frac{adjacent}{hypotenuse}\\\\tan\alpha=\frac{opposite}{adjacent}[/tex] 1) Given that: [tex]cos(22.6\°)=\frac{b}{13}[/tex] You know that b is the adjacent side of the right triangle. To solve for b you must multiply both sides of the expression by 13. Then, the value of b is: [tex]13*cos(22.6\°)=\frac{b}{13}*13\\13*cos(22.6\°)=b\\b=12[/tex] 2) Then, you have that the equation correctly uses the value of b  ( adjacent side) to solve for a (opposite side) is: [tex]tan(22.6\°)=\frac{a}{12}[/tex]