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MATH SOLVE
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Someone help please :(
4 months ago
Q:
Someone help please :(
Accepted Solution
A:
Answer:Step-by-step explanation:Semicircle:diameter = 6 ydr = 6/2 = 3 yd[tex]Area \ of \ semicircle = \dfrac{1}{2}\pi r^{2}\\\\[/tex] [tex]=\dfrac{1}{2}*3.14*3*3\\\\= 14.13 \ yd^{2}[/tex]Triangle:base = b =6 ydheight = h = 4 yd[tex]Area \ of \ triangle = \dfrac{1}{2}bh\\\\[/tex] [tex]=\dfrac{1}{2}*6*4\\\\\\= 3*4\\\\= 12 \ yd^{2}[/tex]Area of composite figure =area of semicircle + area of triangle = 14.13 +12 = 26.13 yd²